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Barron's 2nd Edition DT Q47

  • Writer: keshprad
    keshprad
  • Dec 15, 2019
  • 1 min read

Updated: Feb 14, 2020


47) This question simply asks us to solve for the capacitance of the charged plates. The capacitance is the ratio of the charge to the electric potential. We can use an equation to solve for the capacitance.

Where q is charge, C is capacitance, and V is potential difference

All we need to do is plug in the correct values to find the capacitance.

Where C is capacitance in Farads(F)

Answer: A

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