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Writer's picturekeshprad

Barron's 2nd Edition DT Q47


47) This question simply asks us to solve for the capacitance of the charged plates. The capacitance is the ratio of the charge to the electric potential. We can use an equation to solve for the capacitance.

Where q is charge, C is capacitance, and V is potential difference

All we need to do is plug in the correct values to find the capacitance.

Where C is capacitance in Farads(F)

Answer: A

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