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Writer's picturekeshprad

PhysicsBowl 2017 Q12


12) This question requires us to find the acceleration of the object during the motion described. Problem 12 is a continuation of problem 11, where we found the average velocity. Remember that during the motion, the acceleration is constant, so we can find the average acceleration, which should be the same. Acceleration is the derivative of velocity, so the average acceleration can be expressed as shown.

Where a is acceleration, v is velocity, and t is time

In problem 11, I have already shown how to calculate the final and initial velocity. We need to consider the kinetic energy at the start and end of the motion.

Where K is kinetic energy, m is mass, and v is velocity

The problem tells us that the acceleration is applied for 5 seconds, so we can take t[f] as 5 and t[i] as 0.

Where a is acceleration. v is velocity, and t is time

We just need the magnitude of the acceleration, so our answer is the absolute value of the acceleration.


Answer: D

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