3) This question asks us to consider the object's kinetic energy. Our Kinetic Energy can be modeled by the function below.
Since we just want an approximation of the graph we can simplify this if we neglect the constants. In this equation, there is a coefficient(1/2) and a constant(m). Thus, we end up with this relationship...
Now, we can split the given velocity graph into two sections. For the sake of clarity, part 1 will be blue and part 2 will be orange.
Since we are squaring the velocity, we want to square the y-values of each part of the graph. In part 1 of the given graph, we can see that as time increases, so will velocity. Thus, for our result, as time increases, kinetic energy will increase quadratically. So our final graph be positive, with a positive slope, and concave up.
Finally, in part 2, the graph should look the same as the given graph because we are just looking for an approximation and if we square the y-values in the given graph, we can see it should be positive, with a negative slope, and concave up.
The conditions we described for part 1 and 2 are satisfied by choice B.
Answer: B
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